find the interest rate r for an investment of $1200 that earned $66 in interest for one year|||i=prt
t=1
p=1200
i=66
66=1200*r*1
66=1200r
r=66/1200=.055=5.5%|||x = 66 x 100% ; x =6600/1200; x = 5,5%|||s=prt
t=1
p=1200
s=66
66=1200*r*1
66=1200r
r=66/1200=.055=5.5%|||5.5%.
1200x=66
66/1200|||Remember the formula- Principle * (interest)^(rate * time)
1200(1 + r)^(1) = 1266
1 + r = 1266/1200
r = 66/1200
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