Norton borrowed $1800 form the bank. If he repaid the loan with $3966.76 at the end of 16 years, what interest rate did the bank charge if it was compounded semiannually?
Please explain this to me...I am confused. Thanks|||Let me try to explain.
Imagine, the interest rate is 'a'
Every six months the interest is compounded.
So after the first six months, the principle 'P' becomes
P+ (P*a)/(2*100)
( /2 is because it is interest for half year. )
= P * (200+a) / 200
On completion of the next six months, the principle becomes
P * (200+a) / 200 * (200+a) / 200
So, for every six months, it get multiplied by the factor (200+a) / 200
Let us assume (200+a) / 200 = x
For 16 years or after 32 half years, the principle becomes
P * [(200+a) / 200]^32
Final amount = P * x^32
Putting the known figures, we get
3966.76 = 1800 * x^32
So, x^32 = 3966.76 / 1800 = 2.20376
Hence x = 1.025
ie. (200+a) / 200 = 1.025
There for, The interest rate a = ( 1.025 * 200 ) - 200 = 5
So, Interest rate, a = 5% annually, compounded half yearly.
or
Interest rate is 2.5% half yearly, compounded
You can verify this
1800* ( 1.025 )^32 = 1800 * 2.20376 = 3966.76
Hence proved|||4.9% anually so his interest rate was 4.9/2 %
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